Solve 40-5[10+(5-2*3)^2]^3

$$40 - 5 [ 10 + ( 5 - 2 \times 3 ) ^ { 2 } ] ^ { 3 }$$

Evaluate

$$-6615$$

Solution Steps

Multiply 2 and 3 to get 6.

$$40-5\left(10+\left(5-6\right)^{2}\right)^{3}$$

Subtract 6 from 5 to get -1.

$$40-5\left(10+\left(-1\right)^{2}\right)^{3}$$

Calculate -1 to the power of 2 and get 1.

$$40-5\left(10+1\right)^{3}$$

Add 10 and 1 to get 11.

$$40-5\times 11^{3}$$

Calculate 11 to the power of 3 and get 1331.

$$40-5\times 1331$$

Multiply 5 and 1331 to get 6655.

$$40-6655$$

Subtract 6655 from 40 to get -6615.

$$-6615$$

Factor

$$-6615$$