Solve 40-2[3+8+(12+3)+4-(8-6)]

$$40 - 2 [ 3 + 8 + ( 12 + 3 ) + 4 - ( 8 - 6 ) ]$$

Evaluate

$$-16$$

Solution Steps

Add 3 and 8 to get 11.

$$40-2\left(11+12+3+4-\left(8-6\right)\right)$$

Add 11 and 12 to get 23.

$$40-2\left(23+3+4-\left(8-6\right)\right)$$

Add 23 and 3 to get 26.

$$40-2\left(26+4-\left(8-6\right)\right)$$

Add 26 and 4 to get 30.

$$40-2\left(30-\left(8-6\right)\right)$$

Subtract 6 from 8 to get 2.

$$40-2\left(30-2\right)$$

Subtract 2 from 30 to get 28.

$$40-2\times 28$$

Multiply 2 and 28 to get 56.

$$40-56$$

Subtract 56 from 40 to get -16.

$$-16$$

Factor

$$-16$$