40 \times (1+x \% )=53
Solve for x
x = \frac{65}{2} = 32\frac{1}{2} = 32.5
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1+\frac{x}{100}=\frac{53}{40}
Divide both sides by 40.
200+2x=265
Multiply both sides of the equation by 200, the least common multiple of 100,40.
2x=265-200
Subtract 200 from both sides.
2x=65
Subtract 200 from 265 to get 65.
x=\frac{65}{2}
Divide both sides by 2.
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