Solve 402/5-122/5-(122/5+13/5)div3

$$40 \frac{ 2 }{ 5 } -12 \frac{ 2 }{ 5 } -(12 \frac{ 2 }{ 5 } +1 \frac{ 3 }{ 5 } ) \div 3$$

Evaluate

$$\frac{70}{3}\approx 23.333333333$$

Solution Steps

Multiply 40 and 5 to get 200.

$$\frac{200+2}{5}-\frac{12\times 5+2}{5}-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Add 200 and 2 to get 202.

$$\frac{202}{5}-\frac{12\times 5+2}{5}-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Multiply 12 and 5 to get 60.

$$\frac{202}{5}-\frac{60+2}{5}-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Add 60 and 2 to get 62.

$$\frac{202}{5}-\frac{62}{5}-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Since \frac{202}{5} and \frac{62}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{202-62}{5}-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Subtract 62 from 202 to get 140.

$$\frac{140}{5}-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Divide 140 by 5 to get 28.

$$28-\frac{\frac{12\times 5+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Multiply 12 and 5 to get 60.

$$28-\frac{\frac{60+2}{5}+\frac{1\times 5+3}{5}}{3}$$

Add 60 and 2 to get 62.

$$28-\frac{\frac{62}{5}+\frac{1\times 5+3}{5}}{3}$$

Multiply 1 and 5 to get 5.

$$28-\frac{\frac{62}{5}+\frac{5+3}{5}}{3}$$

Add 5 and 3 to get 8.

$$28-\frac{\frac{62}{5}+\frac{8}{5}}{3}$$

Since \frac{62}{5} and \frac{8}{5} have the same denominator, add them by adding their numerators.

$$28-\frac{\frac{62+8}{5}}{3}$$

Add 62 and 8 to get 70.

$$28-\frac{\frac{70}{5}}{3}$$

Divide 70 by 5 to get 14.

$$28-\frac{14}{3}$$

Convert 28 to fraction \frac{84}{3}.

$$\frac{84}{3}-\frac{14}{3}$$

Since \frac{84}{3} and \frac{14}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{84-14}{3}$$

Subtract 14 from 84 to get 70.

$$\frac{70}{3}$$

Factor

$$\frac{2 \cdot 5 \cdot 7}{3} = 23\frac{1}{3} = 23.333333333333332$$