Solve for B
B=6
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40=10+\frac{7}{3}B+\frac{8}{3}B
Combine B and \frac{4}{3}B to get \frac{7}{3}B.
40=10+5B
Combine \frac{7}{3}B and \frac{8}{3}B to get 5B.
10+5B=40
Swap sides so that all variable terms are on the left hand side.
5B=40-10
Subtract 10 from both sides.
5B=30
Subtract 10 from 40 to get 30.
B=\frac{30}{5}
Divide both sides by 5.
B=6
Divide 30 by 5 to get 6.
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