Solve 40+[40.5/35]*10

$$40 + [ \frac { 40.5 } { 35 } ] \times 10$$

Evaluate

$$\frac{361}{7}\approx 51.571428571$$

Solution Steps

Expand \frac{40.5}{35} by multiplying both numerator and the denominator by 10.

$$40+\frac{405}{350}\times 10$$

Reduce the fraction \frac{405}{350} to lowest terms by extracting and canceling out 5.

$$40+\frac{81}{70}\times 10$$

Express \frac{81}{70}\times 10 as a single fraction.

$$40+\frac{81\times 10}{70}$$

Multiply 81 and 10 to get 810.

$$40+\frac{810}{70}$$

Reduce the fraction \frac{810}{70} to lowest terms by extracting and canceling out 10.

$$40+\frac{81}{7}$$

Convert 40 to fraction \frac{280}{7}.

$$\frac{280}{7}+\frac{81}{7}$$

Since \frac{280}{7} and \frac{81}{7} have the same denominator, add them by adding their numerators.

$$\frac{280+81}{7}$$

Add 280 and 81 to get 361.

$$\frac{361}{7}$$

Factor

$$\frac{19 ^ {2}}{7} = 51\frac{4}{7} = 51.57142857142857$$