Solve 4.9t^2-5t+122.5=0

$$4.9 t ^ { 2 } - 5 t + 122.5 = 0$$

Solve for t

$$t=\frac{25+i\times 30\sqrt{66}}{49}\approx 0.510204082+4.973901064i$$

$$t=\frac{-i\times 30\sqrt{66}+25}{49}\approx 0.510204082-4.973901064i$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$4.9t^{2}-5t+122.5=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 4.9 for a, -5 for b, and 122.5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\times 4.9\times 122.5}}{2\times 4.9}$$

Square -5.

$$t=\frac{-\left(-5\right)±\sqrt{25-4\times 4.9\times 122.5}}{2\times 4.9}$$

Multiply -4 times 4.9.

$$t=\frac{-\left(-5\right)±\sqrt{25-19.6\times 122.5}}{2\times 4.9}$$

Multiply -19.6 times 122.5 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.

$$t=\frac{-\left(-5\right)±\sqrt{25-2401}}{2\times 4.9}$$

Add 25 to -2401.

$$t=\frac{-\left(-5\right)±\sqrt{-2376}}{2\times 4.9}$$

Take the square root of -2376.

$$t=\frac{-\left(-5\right)±6\sqrt{66}i}{2\times 4.9}$$

The opposite of -5 is 5.

$$t=\frac{5±6\sqrt{66}i}{2\times 4.9}$$

Multiply 2 times 4.9.

$$t=\frac{5±6\sqrt{66}i}{9.8}$$

Now solve the equation t=\frac{5±6\sqrt{66}i}{9.8} when ± is plus. Add 5 to 6i\sqrt{66}.

$$t=\frac{5+6\sqrt{66}i}{9.8}$$

Divide 5+6i\sqrt{66} by 9.8 by multiplying 5+6i\sqrt{66} by the reciprocal of 9.8.

$$t=\frac{25+30\sqrt{66}i}{49}$$

Now solve the equation t=\frac{5±6\sqrt{66}i}{9.8} when ± is minus. Subtract 6i\sqrt{66} from 5.

$$t=\frac{-6\sqrt{66}i+5}{9.8}$$

Divide 5-6i\sqrt{66} by 9.8 by multiplying 5-6i\sqrt{66} by the reciprocal of 9.8.

$$t=\frac{-30\sqrt{66}i+25}{49}$$

The equation is now solved.

$$t=\frac{25+30\sqrt{66}i}{49} t=\frac{-30\sqrt{66}i+25}{49}$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$4.9t^{2}-5t+122.5=0$$

Subtract 122.5 from both sides of the equation.

$$4.9t^{2}-5t+122.5-122.5=-122.5$$

Subtracting 122.5 from itself leaves 0.

$$4.9t^{2}-5t=-122.5$$

Divide both sides of the equation by 4.9, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{4.9t^{2}-5t}{4.9}=-\frac{122.5}{4.9}$$

Dividing by 4.9 undoes the multiplication by 4.9.

$$t^{2}+\left(-\frac{5}{4.9}\right)t=-\frac{122.5}{4.9}$$

Divide -5 by 4.9 by multiplying -5 by the reciprocal of 4.9.

$$t^{2}-\frac{50}{49}t=-\frac{122.5}{4.9}$$

Divide -122.5 by 4.9 by multiplying -122.5 by the reciprocal of 4.9.

$$t^{2}-\frac{50}{49}t=-25$$

Divide -\frac{50}{49}, the coefficient of the x term, by 2 to get -\frac{25}{49}. Then add the square of -\frac{25}{49} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$t^{2}-\frac{50}{49}t+\left(-\frac{25}{49}\right)^{2}=-25+\left(-\frac{25}{49}\right)^{2}$$

Square -\frac{25}{49} by squaring both the numerator and the denominator of the fraction.

$$t^{2}-\frac{50}{49}t+\frac{625}{2401}=-25+\frac{625}{2401}$$

Add -25 to \frac{625}{2401}.

$$t^{2}-\frac{50}{49}t+\frac{625}{2401}=-\frac{59400}{2401}$$

Factor t^{2}-\frac{50}{49}t+\frac{625}{2401}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(t-\frac{25}{49}\right)^{2}=-\frac{59400}{2401}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(t-\frac{25}{49}\right)^{2}}=\sqrt{-\frac{59400}{2401}}$$

Simplify.

$$t-\frac{25}{49}=\frac{30\sqrt{66}i}{49} t-\frac{25}{49}=-\frac{30\sqrt{66}i}{49}$$

Add \frac{25}{49} to both sides of the equation.

$$t=\frac{25+30\sqrt{66}i}{49} t=\frac{-30\sqrt{66}i+25}{49}$$