Solve 4.75*8/19+142/3div1.1

$$4.75 \times \frac{ 8 }{ 19 } +14 \frac{ 2 }{ 3 } \div 1.1$$

Evaluate

$$\frac{46}{3}\approx 15.333333333$$

Solution Steps

Convert decimal number 4.75 to fraction \frac{475}{100}. Reduce the fraction \frac{475}{100} to lowest terms by extracting and canceling out 25.

$$\frac{19}{4}\times \frac{8}{19}+\frac{\frac{14\times 3+2}{3}}{1.1}$$

Multiply \frac{19}{4} times \frac{8}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19\times 8}{4\times 19}+\frac{\frac{14\times 3+2}{3}}{1.1}$$

Cancel out 19 in both numerator and denominator.

$$\frac{8}{4}+\frac{\frac{14\times 3+2}{3}}{1.1}$$

Divide 8 by 4 to get 2.

$$2+\frac{\frac{14\times 3+2}{3}}{1.1}$$

Express \frac{\frac{14\times 3+2}{3}}{1.1} as a single fraction.

$$2+\frac{14\times 3+2}{3\times 1.1}$$

Multiply 14 and 3 to get 42.

$$2+\frac{42+2}{3\times 1.1}$$

Add 42 and 2 to get 44.

$$2+\frac{44}{3\times 1.1}$$

Multiply 3 and 1.1 to get 3.3.

$$2+\frac{44}{3.3}$$

Expand \frac{44}{3.3} by multiplying both numerator and the denominator by 10.

$$2+\frac{440}{33}$$

Reduce the fraction \frac{440}{33} to lowest terms by extracting and canceling out 11.

$$2+\frac{40}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}+\frac{40}{3}$$

Since \frac{6}{3} and \frac{40}{3} have the same denominator, add them by adding their numerators.

$$\frac{6+40}{3}$$

Add 6 and 40 to get 46.

$$\frac{46}{3}$$

Factor

$$\frac{2 \cdot 23}{3} = 15\frac{1}{3} = 15.333333333333334$$