Solve 4.2*5x+9.3*z=4000

$$4.2 \times 5x+9.3 \times z=4000$$

Solve for x

$$x=-\frac{31z}{70}+\frac{4000}{21}$$

Steps for Solving Linear Equation

Multiply 4.2 and 5 to get 21.

$$21x+9.3z=4000$$

Subtract 9.3z from both sides.

$$21x=4000-9.3z$$

The equation is in standard form.

$$21x=-\frac{93z}{10}+4000$$

Divide both sides by 21.

$$\frac{21x}{21}=\frac{-\frac{93z}{10}+4000}{21}$$

Dividing by 21 undoes the multiplication by 21.

$$x=\frac{-\frac{93z}{10}+4000}{21}$$

Divide 4000-\frac{93z}{10} by 21.

$$x=-\frac{31z}{70}+\frac{4000}{21}$$

Solve for z

$$z=-\frac{70x}{31}+\frac{40000}{93}$$

Steps for Solving Linear Equation

Multiply 4.2 and 5 to get 21.

$$21x+9.3z=4000$$

Subtract 21x from both sides.

$$9.3z=4000-21x$$

Divide both sides of the equation by 9.3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{9.3z}{9.3}=\frac{4000-21x}{9.3}$$

Dividing by 9.3 undoes the multiplication by 9.3.

$$z=\frac{4000-21x}{9.3}$$

Divide 4000-21x by 9.3 by multiplying 4000-21x by the reciprocal of 9.3.

$$z=-\frac{70x}{31}+\frac{40000}{93}$$