Solve 4.1*5/6+(4.1-34/15)div1.2

$$4.1 \times \frac{ 5 }{ 6 } +(4.1-3 \frac{ 4 }{ 15 } ) \div 1.2$$

Evaluate

$$\frac{37}{9}\approx 4.111111111$$

Solution Steps

Convert decimal number 4.1 to fraction \frac{41}{10}.

$$\frac{41}{10}\times \frac{5}{6}+\frac{4.1-\frac{3\times 15+4}{15}}{1.2}$$

Multiply \frac{41}{10} times \frac{5}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{41\times 5}{10\times 6}+\frac{4.1-\frac{3\times 15+4}{15}}{1.2}$$

Do the multiplications in the fraction \frac{41\times 5}{10\times 6}.

$$\frac{205}{60}+\frac{4.1-\frac{3\times 15+4}{15}}{1.2}$$

Reduce the fraction \frac{205}{60} to lowest terms by extracting and canceling out 5.

$$\frac{41}{12}+\frac{4.1-\frac{3\times 15+4}{15}}{1.2}$$

Multiply 3 and 15 to get 45.

$$\frac{41}{12}+\frac{4.1-\frac{45+4}{15}}{1.2}$$

Add 45 and 4 to get 49.

$$\frac{41}{12}+\frac{4.1-\frac{49}{15}}{1.2}$$

Convert decimal number 4.1 to fraction \frac{41}{10}.

$$\frac{41}{12}+\frac{\frac{41}{10}-\frac{49}{15}}{1.2}$$

Least common multiple of 10 and 15 is 30. Convert \frac{41}{10} and \frac{49}{15} to fractions with denominator 30.

$$\frac{41}{12}+\frac{\frac{123}{30}-\frac{98}{30}}{1.2}$$

Since \frac{123}{30} and \frac{98}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{41}{12}+\frac{\frac{123-98}{30}}{1.2}$$

Subtract 98 from 123 to get 25.

$$\frac{41}{12}+\frac{\frac{25}{30}}{1.2}$$

Reduce the fraction \frac{25}{30} to lowest terms by extracting and canceling out 5.

$$\frac{41}{12}+\frac{\frac{5}{6}}{1.2}$$

Express \frac{\frac{5}{6}}{1.2} as a single fraction.

$$\frac{41}{12}+\frac{5}{6\times 1.2}$$

Multiply 6 and 1.2 to get 7.2.

$$\frac{41}{12}+\frac{5}{7.2}$$

Expand \frac{5}{7.2} by multiplying both numerator and the denominator by 10.

$$\frac{41}{12}+\frac{50}{72}$$

Reduce the fraction \frac{50}{72} to lowest terms by extracting and canceling out 2.

$$\frac{41}{12}+\frac{25}{36}$$

Least common multiple of 12 and 36 is 36. Convert \frac{41}{12} and \frac{25}{36} to fractions with denominator 36.

$$\frac{123}{36}+\frac{25}{36}$$

Since \frac{123}{36} and \frac{25}{36} have the same denominator, add them by adding their numerators.

$$\frac{123+25}{36}$$

Add 123 and 25 to get 148.

$$\frac{148}{36}$$

Reduce the fraction \frac{148}{36} to lowest terms by extracting and canceling out 4.

$$\frac{37}{9}$$

Factor

$$\frac{37}{3 ^ {2}} = 4\frac{1}{9} = 4.111111111111111$$