Solve 4-9/39*21/6

$$4- \frac{ 9 }{ 39 } \times 2 \frac { 1 } { 6 }$$

Evaluate

$$\frac{7}{2}=3.5$$

Solution Steps

Reduce the fraction \frac{9}{39} to lowest terms by extracting and canceling out 3.

$$4-\frac{3}{13}\times \frac{2\times 6+1}{6}$$

Multiply 2 and 6 to get 12.

$$4-\frac{3}{13}\times \frac{12+1}{6}$$

Add 12 and 1 to get 13.

$$4-\frac{3}{13}\times \frac{13}{6}$$

Multiply \frac{3}{13} times \frac{13}{6} by multiplying numerator times numerator and denominator times denominator.

$$4-\frac{3\times 13}{13\times 6}$$

Cancel out 13 in both numerator and denominator.

$$4-\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$4-\frac{1}{2}$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{8}{2}-\frac{1}{2}$$

Since \frac{8}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-1}{2}$$

Subtract 1 from 8 to get 7.

$$\frac{7}{2}$$

Factor

$$\frac{7}{2} = 3\frac{1}{2} = 3.5$$