Solve 4(2x+3)=8(1-x)-5(x-2)

$$4(2x+3)=8(1-x)-5(x-2)$$

Solve for x

$$x=\frac{2}{7}\approx 0.285714286$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4 by 2x+3.

$$8x+12=8\left(1-x\right)-5\left(x-2\right)$$

Use the distributive property to multiply 8 by 1-x.

$$8x+12=8-8x-5\left(x-2\right)$$

Use the distributive property to multiply -5 by x-2.

$$8x+12=8-8x-5x+10$$

Combine -8x and -5x to get -13x.

$$8x+12=8-13x+10$$

Add 8 and 10 to get 18.

$$8x+12=18-13x$$

Add 13x to both sides.

$$8x+12+13x=18$$

Combine 8x and 13x to get 21x.

$$21x+12=18$$

Subtract 12 from both sides.

$$21x=18-12$$

Subtract 12 from 18 to get 6.

$$21x=6$$

Divide both sides by 21.

$$x=\frac{6}{21}$$

Reduce the fraction \frac{6}{21} to lowest terms by extracting and canceling out 3.

$$x=\frac{2}{7}$$