Solve 4(41*13/28)+4(18*13/27)

$$4( \frac{ 41 \times 13 }{ 28 } )+4( \frac{ 18 \times 13 }{ 27 } )$$

Evaluate

$$\frac{2327}{21}\approx 110.80952381$$

Solution Steps

Multiply 41 and 13 to get 533.

$$4\times \frac{533}{28}+4\times \frac{18\times 13}{27}$$

Express 4\times \frac{533}{28} as a single fraction.

$$\frac{4\times 533}{28}+4\times \frac{18\times 13}{27}$$

Multiply 4 and 533 to get 2132.

$$\frac{2132}{28}+4\times \frac{18\times 13}{27}$$

Reduce the fraction \frac{2132}{28} to lowest terms by extracting and canceling out 4.

$$\frac{533}{7}+4\times \frac{18\times 13}{27}$$

Multiply 18 and 13 to get 234.

$$\frac{533}{7}+4\times \frac{234}{27}$$

Reduce the fraction \frac{234}{27} to lowest terms by extracting and canceling out 9.

$$\frac{533}{7}+4\times \frac{26}{3}$$

Express 4\times \frac{26}{3} as a single fraction.

$$\frac{533}{7}+\frac{4\times 26}{3}$$

Multiply 4 and 26 to get 104.

$$\frac{533}{7}+\frac{104}{3}$$

Least common multiple of 7 and 3 is 21. Convert \frac{533}{7} and \frac{104}{3} to fractions with denominator 21.

$$\frac{1599}{21}+\frac{728}{21}$$

Since \frac{1599}{21} and \frac{728}{21} have the same denominator, add them by adding their numerators.

$$\frac{1599+728}{21}$$

Add 1599 and 728 to get 2327.

$$\frac{2327}{21}$$

Factor

$$\frac{13 \cdot 179}{3 \cdot 7} = 110\frac{17}{21} = 110.80952380952381$$