Solve 4(1/8x+1/6)=x-12

$$4( \frac{ 1 }{ 8 } x+ \frac{ 1 }{ 6 } )=x-12$$

Solve for x

$$x = \frac{76}{3} = 25\frac{1}{3} \approx 25.333333333$$

Steps for Solving Linear Equation

Use the distributive property to multiply 4 by \frac{1}{8}x+\frac{1}{6}.

$$4\times \frac{1}{8}x+4\times \frac{1}{6}=x-12$$

Multiply 4 and \frac{1}{8} to get \frac{4}{8}.

$$\frac{4}{8}x+4\times \frac{1}{6}=x-12$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\frac{1}{2}x+4\times \frac{1}{6}=x-12$$

Multiply 4 and \frac{1}{6} to get \frac{4}{6}.

$$\frac{1}{2}x+\frac{4}{6}=x-12$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}x+\frac{2}{3}=x-12$$

Subtract x from both sides.

$$\frac{1}{2}x+\frac{2}{3}-x=-12$$

Combine \frac{1}{2}x and -x to get -\frac{1}{2}x.

$$-\frac{1}{2}x+\frac{2}{3}=-12$$

Subtract \frac{2}{3} from both sides.

$$-\frac{1}{2}x=-12-\frac{2}{3}$$

Convert -12 to fraction -\frac{36}{3}.

$$-\frac{1}{2}x=-\frac{36}{3}-\frac{2}{3}$$

Since -\frac{36}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1}{2}x=\frac{-36-2}{3}$$

Subtract 2 from -36 to get -38.

$$-\frac{1}{2}x=-\frac{38}{3}$$

Multiply both sides by -2, the reciprocal of -\frac{1}{2}.

$$x=-\frac{38}{3}\left(-2\right)$$

Express -\frac{38}{3}\left(-2\right) as a single fraction.

$$x=\frac{-38\left(-2\right)}{3}$$

Multiply -38 and -2 to get 76.

$$x=\frac{76}{3}$$