Solve 4(1/3)-3y=-1

$$4( \frac{ 1 }{ 3 } )-3y=-1$$

Solve for y

$$y=\frac{7}{9}\approx 0.777777778$$

Steps for Solving Linear Equation

Multiply 4 and \frac{1}{3} to get \frac{4}{3}.

$$\frac{4}{3}-3y=-1$$

Subtract \frac{4}{3} from both sides.

$$-3y=-1-\frac{4}{3}$$

Convert -1 to fraction -\frac{3}{3}.

$$-3y=-\frac{3}{3}-\frac{4}{3}$$

Since -\frac{3}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$-3y=\frac{-3-4}{3}$$

Subtract 4 from -3 to get -7.

$$-3y=-\frac{7}{3}$$

Divide both sides by -3.

$$y=\frac{-\frac{7}{3}}{-3}$$

Express \frac{-\frac{7}{3}}{-3} as a single fraction.

$$y=\frac{-7}{3\left(-3\right)}$$

Multiply 3 and -3 to get -9.

$$y=\frac{-7}{-9}$$

Fraction \frac{-7}{-9} can be simplified to \frac{7}{9} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{7}{9}$$