Solve 4,2x-4,8x-6,3x-2,4x

$$4,2 x - 4,8 x - 6,3 x - 2,4 x$$

Evaluate

$$-\frac{93x}{10}$$

Solution Steps

Combine 4,2x and -4,8x to get -0,6x.

$$-0,6x-6,3x-2,4x$$

Combine -0,6x and -6,3x to get -6,9x.

$$-6,9x-2,4x$$

Combine -6,9x and -2,4x to get -9,3x.

$$-9,3x$$

Differentiate w.r.t. x

$$-9,3$$

Steps Using Definition of a Derivative

Combine 4,2x and -4,8x to get -0,6x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-0,6x-6,3x-2,4x)$$

Combine -0,6x and -6,3x to get -6,9x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-6,9x-2,4x)$$

Combine -6,9x and -2,4x to get -9,3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9,3x)$$

The derivative of ax^{n} is nax^{n-1}.

$$-9,3x^{1-1}$$

Subtract 1 from 1.

$$-9,3x^{0}$$

For any term t except 0, t^{0}=1.

$$-9,3$$