Solve 4,1*10^-3+7,9*10^-3

$$4,1 \cdot 10 ^ { - 3 } + 7,9 \cdot 10 ^ { - 3 }$$

Evaluate

$$0,012$$

Solution Steps

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$4,1\times \frac{1}{1000}+7,9\times 10^{-3}$$

Multiply 4,1 and \frac{1}{1000} to get \frac{41}{10000}.

$$\frac{41}{10000}+7,9\times 10^{-3}$$

Calculate 10 to the power of -3 and get \frac{1}{1000}.

$$\frac{41}{10000}+7,9\times \frac{1}{1000}$$

Multiply 7,9 and \frac{1}{1000} to get \frac{79}{10000}.

$$\frac{41}{10000}+\frac{79}{10000}$$

Add \frac{41}{10000} and \frac{79}{10000} to get \frac{3}{250}.

$$\frac{3}{250}$$

Factor

$$\frac{3}{2 \cdot 5 ^ {3}} = 0.012$$