Solve 4+8+2xleft(3+10+2x+7div8right)

$$4+8+2x \left( 3+10+2x+7 \div 8 \right)$$

Evaluate

$$4x^{2}+\frac{111x}{4}+12$$

Solution Steps

Add 4 and 8 to get 12.

$$12+2x\left(3+10+2x+\frac{7}{8}\right)$$

Add 3 and 10 to get 13.

$$12+2x\left(13+2x+\frac{7}{8}\right)$$

Convert 13 to fraction \frac{104}{8}.

$$12+2x\left(\frac{104}{8}+2x+\frac{7}{8}\right)$$

Since \frac{104}{8} and \frac{7}{8} have the same denominator, add them by adding their numerators.

$$12+2x\left(\frac{104+7}{8}+2x\right)$$

Add 104 and 7 to get 111.

$$12+2x\left(\frac{111}{8}+2x\right)$$

Use the distributive property to multiply 2x by \frac{111}{8}+2x.

$$12+2x\times \frac{111}{8}+4x^{2}$$

Express 2\times \frac{111}{8} as a single fraction.

$$12+\frac{2\times 111}{8}x+4x^{2}$$

Multiply 2 and 111 to get 222.

$$12+\frac{222}{8}x+4x^{2}$$

Reduce the fraction \frac{222}{8} to lowest terms by extracting and canceling out 2.

$$12+\frac{111}{4}x+4x^{2}$$

Expand

$$4x^{2}+\frac{111x}{4}+12$$

Solution Steps

Add 4 and 8 to get 12.

$$12+2x\left(3+10+2x+\frac{7}{8}\right)$$

Add 3 and 10 to get 13.

$$12+2x\left(13+2x+\frac{7}{8}\right)$$

Convert 13 to fraction \frac{104}{8}.

$$12+2x\left(\frac{104}{8}+2x+\frac{7}{8}\right)$$

Since \frac{104}{8} and \frac{7}{8} have the same denominator, add them by adding their numerators.

$$12+2x\left(\frac{104+7}{8}+2x\right)$$

Add 104 and 7 to get 111.

$$12+2x\left(\frac{111}{8}+2x\right)$$

Use the distributive property to multiply 2x by \frac{111}{8}+2x.

$$12+2x\times \frac{111}{8}+4x^{2}$$

Express 2\times \frac{111}{8} as a single fraction.

$$12+\frac{2\times 111}{8}x+4x^{2}$$

Multiply 2 and 111 to get 222.

$$12+\frac{222}{8}x+4x^{2}$$

Reduce the fraction \frac{222}{8} to lowest terms by extracting and canceling out 2.

$$12+\frac{111}{4}x+4x^{2}$$