Solve 4+3sqrt{2y}=6

$$4+3 \sqrt{ 2y } =6$$

Solve for y

$$y=\frac{2}{9}\approx 0.222222222$$

Steps for Solving Radical Equations

Subtract 4 from both sides of the equation.

$$3\sqrt{2y}+4-4=6-4$$

Subtracting 4 from itself leaves 0.

$$3\sqrt{2y}=6-4$$

Subtract 4 from 6.

$$3\sqrt{2y}=2$$

Divide both sides by 3.

$$\frac{3\sqrt{2y}}{3}=\frac{2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$\sqrt{2y}=\frac{2}{3}$$

Square both sides of the equation.

$$2y=\frac{4}{9}$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{\frac{4}{9}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{\frac{4}{9}}{2}$$

Divide \frac{4}{9} by 2.

$$y=\frac{2}{9}$$