Solve 4+144+32-120+72+lambdaleft(74+4-96right)=0

$$4+144+32-120+72+ \lambda \left( 74+4-96 \right) =0$$

Solve for λ

$$\lambda =\frac{22}{3}\approx 7.333333333$$

Steps for Solving Linear Equation

Add 4 and 144 to get 148.

$$148+32-120+72+\lambda \left(74+4-96\right)=0$$

Add 148 and 32 to get 180.

$$180-120+72+\lambda \left(74+4-96\right)=0$$

Subtract 120 from 180 to get 60.

$$60+72+\lambda \left(74+4-96\right)=0$$

Add 60 and 72 to get 132.

$$132+\lambda \left(74+4-96\right)=0$$

Add 74 and 4 to get 78.

$$132+\lambda \left(78-96\right)=0$$

Subtract 96 from 78 to get -18.

$$132+\lambda \left(-18\right)=0$$

Subtract 132 from both sides. Anything subtracted from zero gives its negation.

$$\lambda \left(-18\right)=-132$$

Divide both sides by -18.

$$\lambda =\frac{-132}{-18}$$

Reduce the fraction \frac{-132}{-18} to lowest terms by extracting and canceling out -6.

$$\lambda =\frac{22}{3}$$