Solve 4+x^2=0+3

$$4+ { x }^{ 2 } = 0+3$$

Solve for x (complex solution)

$$x=-i$$

$$x=i$$

Steps by Finding Square Root

Add 0 and 3 to get 3.

$$4+x^{2}=3$$

Subtract 4 from both sides.

$$x^{2}=3-4$$

Subtract 4 from 3 to get -1.

$$x^{2}=-1$$

The equation is now solved.

$$x=i x=-i$$

Steps Using the Quadratic Formula

Add 0 and 3 to get 3.

$$4+x^{2}=3$$

Subtract 3 from both sides.

$$4+x^{2}-3=0$$

Subtract 3 from 4 to get 1.

$$1+x^{2}=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$x^{2}+1=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4}}{2}$$

Take the square root of -4.

$$x=\frac{0±2i}{2}$$

Now solve the equation x=\frac{0±2i}{2} when ± is plus.

$$x=i$$

Now solve the equation x=\frac{0±2i}{2} when ± is minus.

$$x=-i$$

The equation is now solved.

$$x=i x=-i$$