Solve for x
x=\frac{y-3}{2}
Solve for y
y=2x+3
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-8x=12-4y
Subtract 4y from both sides.
\frac{-8x}{-8}=\frac{12-4y}{-8}
Divide both sides by -8.
x=\frac{12-4y}{-8}
Dividing by -8 undoes the multiplication by -8.
x=\frac{y-3}{2}
Divide 12-4y by -8.
4y=12+8x
Add 8x to both sides.
4y=8x+12
The equation is in standard form.
\frac{4y}{4}=\frac{8x+12}{4}
Divide both sides by 4.
y=\frac{8x+12}{4}
Dividing by 4 undoes the multiplication by 4.
y=2x+3
Divide 12+8x by 4.
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