Solve for x
x=\frac{y}{2}-\frac{1}{8}
Solve for y
y=2x+\frac{1}{4}
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8x=4y-1
Swap sides so that all variable terms are on the left hand side.
\frac{8x}{8}=\frac{4y-1}{8}
Divide both sides by 8.
x=\frac{4y-1}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{y}{2}-\frac{1}{8}
Divide 4y-1 by 8.
4y=8x+1
Add 1 to both sides.
\frac{4y}{4}=\frac{8x+1}{4}
Divide both sides by 4.
y=\frac{8x+1}{4}
Dividing by 4 undoes the multiplication by 4.
y=2x+\frac{1}{4}
Divide 8x+1 by 4.
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