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y\left(4y+24\right)=0
Factor out y.
y=0 y=-6
To find equation solutions, solve y=0 and 4y+24=0.
4y^{2}+24y=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-24±\sqrt{24^{2}}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 24 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-24±24}{2\times 4}
Take the square root of 24^{2}.
y=\frac{-24±24}{8}
Multiply 2 times 4.
y=\frac{0}{8}
Now solve the equation y=\frac{-24±24}{8} when ± is plus. Add -24 to 24.
y=0
Divide 0 by 8.
y=-\frac{48}{8}
Now solve the equation y=\frac{-24±24}{8} when ± is minus. Subtract 24 from -24.
y=-6
Divide -48 by 8.
y=0 y=-6
The equation is now solved.
4y^{2}+24y=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{4y^{2}+24y}{4}=\frac{0}{4}
Divide both sides by 4.
y^{2}+\frac{24}{4}y=\frac{0}{4}
Dividing by 4 undoes the multiplication by 4.
y^{2}+6y=\frac{0}{4}
Divide 24 by 4.
y^{2}+6y=0
Divide 0 by 4.
y^{2}+6y+3^{2}=3^{2}
Divide 6, the coefficient of the x term, by 2 to get 3. Then add the square of 3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}+6y+9=9
Square 3.
\left(y+3\right)^{2}=9
Factor y^{2}+6y+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y+3\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
y+3=3 y+3=-3
Simplify.
y=0 y=-6
Subtract 3 from both sides of the equation.