Solve for x
x=\frac{8-4y}{3}
Solve for y
y=-\frac{3x}{4}+2
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-3x+8=4y
Swap sides so that all variable terms are on the left hand side.
-3x=4y-8
Subtract 8 from both sides.
\frac{-3x}{-3}=\frac{4y-8}{-3}
Divide both sides by -3.
x=\frac{4y-8}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{8-4y}{3}
Divide -8+4y by -3.
4y=8-3x
The equation is in standard form.
\frac{4y}{4}=\frac{8-3x}{4}
Divide both sides by 4.
y=\frac{8-3x}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{3x}{4}+2
Divide -3x+8 by 4.
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