Solve 4y+4=-8/3x

$$4 y + 4 = - \frac { 8 } { 3 } x$$

Solve for x

$$x=\frac{-3y-3}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{8}{3}x=4y+4$$

Divide both sides of the equation by -\frac{8}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{8}{3}x}{-\frac{8}{3}}=\frac{4y+4}{-\frac{8}{3}}$$

Dividing by -\frac{8}{3} undoes the multiplication by -\frac{8}{3}.

$$x=\frac{4y+4}{-\frac{8}{3}}$$

Divide 4+4y by -\frac{8}{3} by multiplying 4+4y by the reciprocal of -\frac{8}{3}.

$$x=\frac{-3y-3}{2}$$

Solve for y

$$y=-\frac{2x}{3}-1$$

Steps for Solving Linear Equation

Subtract 4 from both sides.

$$4y=-\frac{8}{3}x-4$$

The equation is in standard form.

$$4y=-\frac{8x}{3}-4$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{-\frac{8x}{3}-4}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{-\frac{8x}{3}-4}{4}$$

Divide -\frac{8x}{3}-4 by 4.

$$y=-\frac{2x}{3}-1$$