Solve 4y+2<8y-(6y-10)

$$4 y + 2 < 8 y - ( 6 y - 10 )$$

Solve for y

$$y<4$$

Solution Steps

To find the opposite of 6y-10, find the opposite of each term.

$$4y+2<8y-6y-\left(-10\right)$$

The opposite of -10 is 10.

$$4y+2<8y-6y+10$$

Combine 8y and -6y to get 2y.

$$4y+2<2y+10$$

Subtract 2y from both sides.

$$4y+2-2y<10$$

Combine 4y and -2y to get 2y.

$$2y+2<10$$

Subtract 2 from both sides.

$$2y<10-2$$

Subtract 2 from 10 to get 8.

$$2y<8$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$y<\frac{8}{2}$$

Divide 8 by 2 to get 4.

$$y<4$$