Solve for x
x=-\frac{y}{3}-\frac{13}{2}
Solve for y
y=-3x-\frac{39}{2}
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12x=-78-4y
Subtract 4y from both sides.
12x=-4y-78
The equation is in standard form.
\frac{12x}{12}=\frac{-4y-78}{12}
Divide both sides by 12.
x=\frac{-4y-78}{12}
Dividing by 12 undoes the multiplication by 12.
x=-\frac{y}{3}-\frac{13}{2}
Divide -78-4y by 12.
4y=-78-12x
Subtract 12x from both sides.
4y=-12x-78
The equation is in standard form.
\frac{4y}{4}=\frac{-12x-78}{4}
Divide both sides by 4.
y=\frac{-12x-78}{4}
Dividing by 4 undoes the multiplication by 4.
y=-3x-\frac{39}{2}
Divide -78-12x by 4.
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