Solve 4y+1/3=7/9

$$4 y + \frac { 1 } { 3 } = \frac { 7 } { 9 }$$

Solve for y

$$y=\frac{1}{9}\approx 0.111111111$$

Steps for Solving Linear Equation

Subtract \frac{1}{3} from both sides.

$$4y=\frac{7}{9}-\frac{1}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{7}{9} and \frac{1}{3} to fractions with denominator 9.

$$4y=\frac{7}{9}-\frac{3}{9}$$

Since \frac{7}{9} and \frac{3}{9} have the same denominator, subtract them by subtracting their numerators.

$$4y=\frac{7-3}{9}$$

Subtract 3 from 7 to get 4.

$$4y=\frac{4}{9}$$

Divide both sides by 4.

$$y=\frac{\frac{4}{9}}{4}$$

Express \frac{\frac{4}{9}}{4} as a single fraction.

$$y=\frac{4}{9\times 4}$$

Cancel out 4 in both numerator and denominator.

$$y=\frac{1}{9}$$