Solve 4xy+3y=4x

$$4 x y + 3 y = 4 x$$

Solve for x

$$x=-\frac{3y}{4\left(y-1\right)}$$

$$y\neq 1$$

Steps for Solving Linear Equation

Subtract 4x from both sides.

$$4xy+3y-4x=0$$

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$4xy-4x=-3y$$

Combine all terms containing x.

$$\left(4y-4\right)x=-3y$$

Divide both sides by 4y-4.

$$\frac{\left(4y-4\right)x}{4y-4}=-\frac{3y}{4y-4}$$

Dividing by 4y-4 undoes the multiplication by 4y-4.

$$x=-\frac{3y}{4y-4}$$

Divide -3y by 4y-4.

$$x=-\frac{3y}{4\left(y-1\right)}$$

Solve for y

$$y=\frac{4x}{4x+3}$$

$$x\neq -\frac{3}{4}$$

Steps for Solving Linear Equation

Combine all terms containing y.

$$\left(4x+3\right)y=4x$$

Divide both sides by 4x+3.

$$\frac{\left(4x+3\right)y}{4x+3}=\frac{4x}{4x+3}$$

Dividing by 4x+3 undoes the multiplication by 4x+3.

$$y=\frac{4x}{4x+3}$$