Solve 4x_{1}+6xz=22

$$4 x _ { 1 } + 6 x z = 22$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{2x_{1}-11}{3z}\text{, }&z\neq 0\\x\in \mathrm{R}\text{, }&x_{1}=\frac{11}{2}\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 4x_{1} from both sides.

$$6xz=22-4x_{1}$$

The equation is in standard form.

$$6zx=22-4x_{1}$$

Divide both sides by 6z.

$$\frac{6zx}{6z}=\frac{22-4x_{1}}{6z}$$

Dividing by 6z undoes the multiplication by 6z.

$$x=\frac{22-4x_{1}}{6z}$$

Divide 22-4x_{1} by 6z.

$$x=\frac{11-2x_{1}}{3z}$$

Solve for x_1

$$x_{1}=\frac{11-3xz}{2}$$

Steps for Solving Linear Equation

Subtract 6xz from both sides.

$$4x_{1}=22-6xz$$

Divide both sides by 4.

$$\frac{4x_{1}}{4}=\frac{22-6xz}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x_{1}=\frac{22-6xz}{4}$$

Divide 22-6xz by 4.

$$x_{1}=\frac{11-3xz}{2}$$