Solve for x
x=\frac{7\left(y-8\right)}{4}
Solve for y
y=\frac{4\left(x+14\right)}{7}
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4x=-56+7y
Add 7y to both sides.
4x=7y-56
The equation is in standard form.
\frac{4x}{4}=\frac{7y-56}{4}
Divide both sides by 4.
x=\frac{7y-56}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{7y}{4}-14
Divide -56+7y by 4.
-7y=-56-4x
Subtract 4x from both sides.
-7y=-4x-56
The equation is in standard form.
\frac{-7y}{-7}=\frac{-4x-56}{-7}
Divide both sides by -7.
y=\frac{-4x-56}{-7}
Dividing by -7 undoes the multiplication by -7.
y=\frac{4x}{7}+8
Divide -56-4x by -7.
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Limits
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