Solve for x
x=\frac{7\left(y-5\right)}{4}
Solve for y
y=\frac{4x}{7}+5
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4x=-35+7y
Add 7y to both sides.
4x=7y-35
The equation is in standard form.
\frac{4x}{4}=\frac{7y-35}{4}
Divide both sides by 4.
x=\frac{7y-35}{4}
Dividing by 4 undoes the multiplication by 4.
-7y=-35-4x
Subtract 4x from both sides.
-7y=-4x-35
The equation is in standard form.
\frac{-7y}{-7}=\frac{-4x-35}{-7}
Divide both sides by -7.
y=\frac{-4x-35}{-7}
Dividing by -7 undoes the multiplication by -7.
y=\frac{4x}{7}+5
Divide -35-4x by -7.
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y = 3x + 4
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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