Solve for x
x=\frac{3y-11}{4}
Solve for y
y=\frac{4x+11}{3}
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4x+11=3y
Add 3y to both sides. Anything plus zero gives itself.
4x=3y-11
Subtract 11 from both sides.
\frac{4x}{4}=\frac{3y-11}{4}
Divide both sides by 4.
x=\frac{3y-11}{4}
Dividing by 4 undoes the multiplication by 4.
-3y+11=-4x
Subtract 4x from both sides. Anything subtracted from zero gives its negation.
-3y=-4x-11
Subtract 11 from both sides.
\frac{-3y}{-3}=\frac{-4x-11}{-3}
Divide both sides by -3.
y=\frac{-4x-11}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{4x+11}{3}
Divide -4x-11 by -3.
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Limits
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