Solve 4x-sqrt{3}=xsqrt{3}-4

$$4 x - \sqrt { 3 } = x \sqrt { 3 } - 4$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Subtract x\sqrt{3} from both sides.

$$4x-\sqrt{3}-x\sqrt{3}=-4$$

Add \sqrt{3} to both sides.

$$4x-x\sqrt{3}=-4+\sqrt{3}$$

Combine all terms containing x.

$$\left(4-\sqrt{3}\right)x=-4+\sqrt{3}$$

The equation is in standard form.

$$\left(4-\sqrt{3}\right)x=\sqrt{3}-4$$

Divide both sides by 4-\sqrt{3}.

$$\frac{\left(4-\sqrt{3}\right)x}{4-\sqrt{3}}=\frac{\sqrt{3}-4}{4-\sqrt{3}}$$

Dividing by 4-\sqrt{3} undoes the multiplication by 4-\sqrt{3}.

$$x=\frac{\sqrt{3}-4}{4-\sqrt{3}}$$

Divide -4+\sqrt{3} by 4-\sqrt{3}.

$$x=-1$$