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4x\left(1+\frac{12}{25}\right)^{t}=19
Reduce the fraction \frac{48}{100} to lowest terms by extracting and canceling out 4.
4x\times \left(\frac{37}{25}\right)^{t}=19
Add 1 and \frac{12}{25} to get \frac{37}{25}.
4\times \left(\frac{37}{25}\right)^{t}x=19
The equation is in standard form.
\frac{4\times \left(\frac{37}{25}\right)^{t}x}{4\times \left(\frac{37}{25}\right)^{t}}=\frac{19}{4\times \left(\frac{37}{25}\right)^{t}}
Divide both sides by 4\times \left(\frac{37}{25}\right)^{t}.
x=\frac{19}{4\times \left(\frac{37}{25}\right)^{t}}
Dividing by 4\times \left(\frac{37}{25}\right)^{t} undoes the multiplication by 4\times \left(\frac{37}{25}\right)^{t}.
x=\frac{19\times \left(\frac{25}{37}\right)^{t}}{4}
Divide 19 by 4\times \left(\frac{37}{25}\right)^{t}.