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\left(2x^{4}-y^{5}\right)\left(2x^{4}+y^{5}\right)
Rewrite 4x^{8}-y^{10} as \left(2x^{4}\right)^{2}-\left(y^{5}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).