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4\left(x^{3}y-11x^{2}y+28xy\right)
Factor out 4.
xy\left(x^{2}-11x+28\right)
Consider x^{3}y-11x^{2}y+28xy. Factor out xy.
a+b=-11 ab=1\times 28=28
Consider x^{2}-11x+28. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+28. To find a and b, set up a system to be solved.
-1,-28 -2,-14 -4,-7
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 28.
-1-28=-29 -2-14=-16 -4-7=-11
Calculate the sum for each pair.
a=-7 b=-4
The solution is the pair that gives sum -11.
\left(x^{2}-7x\right)+\left(-4x+28\right)
Rewrite x^{2}-11x+28 as \left(x^{2}-7x\right)+\left(-4x+28\right).
x\left(x-7\right)-4\left(x-7\right)
Factor out x in the first and -4 in the second group.
\left(x-7\right)\left(x-4\right)
Factor out common term x-7 by using distributive property.
4xy\left(x-7\right)\left(x-4\right)
Rewrite the complete factored expression.