Solve 4x^3-64x

$$4 x ^ { 3 } - 64 x$$

Factor

$$4x\left(x-4\right)\left(x+4\right)$$

Solution Steps

Factor out 4.

$$4\left(x^{3}-16x\right)$$

Consider x^{3}-16x. Factor out x.

$$x\left(x^{2}-16\right)$$

Consider x^{2}-16. Rewrite x^{2}-16 as x^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-4\right)\left(x+4\right)$$

Rewrite the complete factored expression.

$$4x\left(x-4\right)\left(x+4\right)$$

Evaluate

$$4x\left(x^{2}-16\right)$$