Solve 4x^3*5x^2y*2xy^3

$$4 x ^ { 3 } \times 5 x ^ { 2 } y \times 2 x y ^ { 3 }$$

Evaluate

$$40y^{4}x^{6}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$4x^{5}\times 5y\times 2xy^{3}$$

To multiply powers of the same base, add their exponents. Add 5 and 1 to get 6.

$$4x^{6}\times 5y\times 2y^{3}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$4x^{6}\times 5y^{4}\times 2$$

Multiply 4 and 5 to get 20.

$$20x^{6}y^{4}\times 2$$

Multiply 20 and 2 to get 40.

$$40x^{6}y^{4}$$

Differentiate w.r.t. x

$$240y^{4}x^{5}$$