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4x^{2}-50-58=x^{2}
Subtract 58 from both sides.
4x^{2}-108=x^{2}
Subtract 58 from -50 to get -108.
4x^{2}-108-x^{2}=0
Subtract x^{2} from both sides.
3x^{2}-108=0
Combine 4x^{2} and -x^{2} to get 3x^{2}.
x^{2}-36=0
Divide both sides by 3.
\left(x-6\right)\left(x+6\right)=0
Consider x^{2}-36. Rewrite x^{2}-36 as x^{2}-6^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=6 x=-6
To find equation solutions, solve x-6=0 and x+6=0.
4x^{2}-50-x^{2}=58
Subtract x^{2} from both sides.
3x^{2}-50=58
Combine 4x^{2} and -x^{2} to get 3x^{2}.
3x^{2}=58+50
Add 50 to both sides.
3x^{2}=108
Add 58 and 50 to get 108.
x^{2}=\frac{108}{3}
Divide both sides by 3.
x^{2}=36
Divide 108 by 3 to get 36.
x=6 x=-6
Take the square root of both sides of the equation.
4x^{2}-50-58=x^{2}
Subtract 58 from both sides.
4x^{2}-108=x^{2}
Subtract 58 from -50 to get -108.
4x^{2}-108-x^{2}=0
Subtract x^{2} from both sides.
3x^{2}-108=0
Combine 4x^{2} and -x^{2} to get 3x^{2}.
x=\frac{0±\sqrt{0^{2}-4\times 3\left(-108\right)}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -108 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 3\left(-108\right)}}{2\times 3}
Square 0.
x=\frac{0±\sqrt{-12\left(-108\right)}}{2\times 3}
Multiply -4 times 3.
x=\frac{0±\sqrt{1296}}{2\times 3}
Multiply -12 times -108.
x=\frac{0±36}{2\times 3}
Take the square root of 1296.
x=\frac{0±36}{6}
Multiply 2 times 3.
x=6
Now solve the equation x=\frac{0±36}{6} when ± is plus. Divide 36 by 6.
x=-6
Now solve the equation x=\frac{0±36}{6} when ± is minus. Divide -36 by 6.
x=6 x=-6
The equation is now solved.