Factor
\frac{\left(10x-5y-1\right)\left(10x-5y+1\right)}{25}
Evaluate
\left(2x-y\right)^{2}-\frac{1}{25}
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\frac{100x^{2}-100xy+25y^{2}-1}{25}
Factor out \frac{1}{25}.
\left(10x-5y-1\right)\left(10x-5y+1\right)
Consider 100x^{2}-100xy+25y^{2}-1. Rewrite 100x^{2}-100xy+25y^{2}-1 as \left(10x-5y\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(10x-5y-1\right)\left(10x-5y+1\right)}{25}
Rewrite the complete factored expression.
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