Solve 4x^2-4x-48-x^2+x-20=3x^2+9x-30

$$4 x ^ { 2 } - 4 x - 48 - x ^ { 2 } + x - 20 = 3 x ^ { 2 } + 9 x - 30$$

Solve for x

$$x = -\frac{19}{6} = -3\frac{1}{6} \approx -3.166666667$$

Steps for Solving Linear Equation

Combine 4x^{2} and -x^{2} to get 3x^{2}.

$$3x^{2}-4x-48+x-20=3x^{2}+9x-30$$

Combine -4x and x to get -3x.

$$3x^{2}-3x-48-20=3x^{2}+9x-30$$

Subtract 20 from -48 to get -68.

$$3x^{2}-3x-68=3x^{2}+9x-30$$

Subtract 3x^{2} from both sides.

$$3x^{2}-3x-68-3x^{2}=9x-30$$

Combine 3x^{2} and -3x^{2} to get 0.

$$-3x-68=9x-30$$

Subtract 9x from both sides.

$$-3x-68-9x=-30$$

Combine -3x and -9x to get -12x.

$$-12x-68=-30$$

Add 68 to both sides.

$$-12x=-30+68$$

Add -30 and 68 to get 38.

$$-12x=38$$

Divide both sides by -12.

$$x=\frac{38}{-12}$$

Reduce the fraction \frac{38}{-12} to lowest terms by extracting and canceling out 2.

$$x=-\frac{19}{6}$$