Solve 4x^2-2xy+y^2/2

$$4 x ^ { 2 } - 2 x y + y ^ { 2 } / 2$$

Evaluate

$$-2xy+\frac{y^{2}}{2}+4x^{2}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 4x^{2}-2xy times \frac{2}{2}.

$$\frac{2\left(4x^{2}-2xy\right)}{2}+\frac{y^{2}}{2}$$

Since \frac{2\left(4x^{2}-2xy\right)}{2} and \frac{y^{2}}{2} have the same denominator, add them by adding their numerators.

$$\frac{2\left(4x^{2}-2xy\right)+y^{2}}{2}$$

Do the multiplications in 2\left(4x^{2}-2xy\right)+y^{2}.

$$\frac{8x^{2}-4xy+y^{2}}{2}$$

Factor

$$\frac{8x^{2}-4xy+y^{2}}{2}$$

Solution Steps

Factor out \frac{1}{2}.

$$\frac{8x^{2}-4xy+y^{2}}{2}$$