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\frac{64x^{2}-1}{16}
Factor out \frac{1}{16}.
\left(8x-1\right)\left(8x+1\right)
Consider 64x^{2}-1. Rewrite 64x^{2}-1 as \left(8x\right)^{2}-1^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(8x-1\right)\left(8x+1\right)}{16}
Rewrite the complete factored expression.