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x\left(4x+8\right)=0
Factor out x.
x=0 x=-2
To find equation solutions, solve x=0 and 4x+8=0.
4x^{2}+8x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-8±\sqrt{8^{2}}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 8 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-8±8}{2\times 4}
Take the square root of 8^{2}.
x=\frac{-8±8}{8}
Multiply 2 times 4.
x=\frac{0}{8}
Now solve the equation x=\frac{-8±8}{8} when ± is plus. Add -8 to 8.
x=0
Divide 0 by 8.
x=-\frac{16}{8}
Now solve the equation x=\frac{-8±8}{8} when ± is minus. Subtract 8 from -8.
x=-2
Divide -16 by 8.
x=0 x=-2
The equation is now solved.
4x^{2}+8x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{4x^{2}+8x}{4}=\frac{0}{4}
Divide both sides by 4.
x^{2}+\frac{8}{4}x=\frac{0}{4}
Dividing by 4 undoes the multiplication by 4.
x^{2}+2x=\frac{0}{4}
Divide 8 by 4.
x^{2}+2x=0
Divide 0 by 4.
x^{2}+2x+1^{2}=1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=1
Square 1.
\left(x+1\right)^{2}=1
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
x+1=1 x+1=-1
Simplify.
x=0 x=-2
Subtract 1 from both sides of the equation.