Solve 4x^2+3y=2

$$4 x ^ { 2 } + 3 y = 2$$

Solve for y

$$y=\frac{2-4x^{2}}{3}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides.

$$3y=2-4x^{2}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{2-4x^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{2-4x^{2}}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{2-3y}}{2}$$

$$x=\frac{\sqrt{2-3y}}{2}$$

Solve for x

$$x=\frac{\sqrt{2-3y}}{2}$$

$$x=-\frac{\sqrt{2-3y}}{2}\text{, }y\leq \frac{2}{3}$$