Solve 4x^2+10y-7=0

$$4 x ^ { 2 } + 10 y - 7 = 0$$

Solve for y

$$y=-\frac{2x^{2}}{5}+\frac{7}{10}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides. Anything subtracted from zero gives its negation.

$$10y-7=-4x^{2}$$

Add 7 to both sides.

$$10y=-4x^{2}+7$$

The equation is in standard form.

$$10y=7-4x^{2}$$

Divide both sides by 10.

$$\frac{10y}{10}=\frac{7-4x^{2}}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$y=\frac{7-4x^{2}}{10}$$

Divide -4x^{2}+7 by 10.

$$y=-\frac{2x^{2}}{5}+\frac{7}{10}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{7-10y}}{2}$$

$$x=\frac{\sqrt{7-10y}}{2}$$

Solve for x

$$x=\frac{\sqrt{7-10y}}{2}$$

$$x=-\frac{\sqrt{7-10y}}{2}\text{, }y\leq \frac{7}{10}$$