Solve 4x+6+8y=x-5

$$4 x + 6 + 8 y = x - 5$$

Solve for x

$$x=\frac{-8y-11}{3}$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$4x+6+8y-x=-5$$

Combine 4x and -x to get 3x.

$$3x+6+8y=-5$$

Subtract 6 from both sides.

$$3x+8y=-5-6$$

Subtract 6 from -5 to get -11.

$$3x+8y=-11$$

Subtract 8y from both sides.

$$3x=-11-8y$$

The equation is in standard form.

$$3x=-8y-11$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{-8y-11}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{-8y-11}{3}$$

Solve for y

$$y=\frac{-3x-11}{8}$$

Steps for Solving Linear Equation

Subtract 4x from both sides.

$$6+8y=x-5-4x$$

Combine x and -4x to get -3x.

$$6+8y=-3x-5$$

Subtract 6 from both sides.

$$8y=-3x-5-6$$

Subtract 6 from -5 to get -11.

$$8y=-3x-11$$

Divide both sides by 8.

$$\frac{8y}{8}=\frac{-3x-11}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$y=\frac{-3x-11}{8}$$