Solve for x
x=-\frac{3y}{4}+3
Solve for y
y=-\frac{4x}{3}+4
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4x-12=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
4x=-3y+12
Add 12 to both sides.
4x=12-3y
The equation is in standard form.
\frac{4x}{4}=\frac{12-3y}{4}
Divide both sides by 4.
x=\frac{12-3y}{4}
Dividing by 4 undoes the multiplication by 4.
x=-\frac{3y}{4}+3
Divide -3y+12 by 4.
3y-12=-4x
Subtract 4x from both sides. Anything subtracted from zero gives its negation.
3y=-4x+12
Add 12 to both sides.
3y=12-4x
The equation is in standard form.
\frac{3y}{3}=\frac{12-4x}{3}
Divide both sides by 3.
y=\frac{12-4x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{4x}{3}+4
Divide -4x+12 by 3.
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